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enyata [817]
1 year ago
6

Find the limit, please

Mathematics
1 answer:
tino4ka555 [31]1 year ago
4 0

Answer:

I think it's uhm twelve I'm not 100% sure though

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Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

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a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

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