Question

What is the value of sin(t) if cos(t)=0.1, and t is in quadrant 1

Answer 1

Answer:

$sin(t)=\frac{\sqrt{99}}{10}$

Step-by-step explanation:

Remember that

If angle t belong to the First Quadrant

then

The value of sin(t) and cos(t) are positive values

we know that

$sin^2(t)+cos^2(t)=1$ ---> by trigonometric identity

we have

$cos(t)=0.1=\frac{1}{10}$

substitute

$sin^2(t)+(\frac{1}{10})^2=1$

$sin^2(t)+\frac{1}{100}=1$

$sin^2(t)=1-\frac{1}{100}$

$sin^2(t)=\frac{99}{100}$

$sin(t)=\frac{\sqrt{99}}{10}$