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Ksenya-84 [330]
4 years ago
5

Which expression is equivalent to 16x²-36

Mathematics
2 answers:
Rudik [331]4 years ago
4 0
The answer is -4 because I use a calculater
LiRa [457]4 years ago
4 0
A possibility is (4x+6)(4x-6)
This is due to difference of squares in algebra. Since 16x^2 is a square, and 36 is a square, and 36 is being subtracted from 16x^2, then this method can be used.
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Mae has a number cube with 6 sides that are numbered 1 through 6. What is the probability that Mae will roll an odd number?
Stels [109]

Answer:

C) P(E)  = \frac{3}{6}<u></u>

The probability that Mae will roll an odd number

<u></u>P(E)  = \frac{3}{6}<u></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that Mae has a number cube with 6 sides that are numbered 1 through 6.</em>

<em>n(S) = { 1,2,3,4,5,6,} = 6</em>

<em>Let 'E ' be the event of odd numbers</em>

<em>Mae will roll an odd number</em>

<em>n(E) = {1, 3, 5} = 3</em>

<u>Step(ii):-</u>

<u>The probability that Mae will roll an odd number</u>

<u></u>P(E) = \frac{n(E)}{n(S)} = \frac{3}{6}<u></u>

<u></u>P(E)  = \frac{3}{6}<u></u>

4 0
3 years ago
A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature
Westkost [7]

Answer:

(a) The value of <em>k</em> is \frac{1}{15}.

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d)  P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of <em>k</em>.

\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}

Thus, the value of <em>k</em> is \frac{1}{15}.

(b)

Compute the value of P (Y ≤ 3) as follows:

P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\   =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 to be the pmf of Y it has to satisfy the conditions:

  1. P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\
  2. \sum P(y)=1

<u>Check condition 1:</u>

y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0

Condition 1 is fulfilled.

<u>Check condition 2:</u>

\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1

Condition 2 is not satisfied.

Thus, P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

7 0
3 years ago
A street light is at the top of a 11 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 7 ft/sec along a s
zheka24 [161]

Answer:

The answer is 8.5 Ft/Sec.

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

Step-by-step explanation:

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

The solution and explanation is attached.

Download pdf
7 0
3 years ago
1. If a polynomial of Degree 4 has an imaginary zero at -2i and a real zero at 5, how many imaginary zeros does it have?
Vadim26 [7]

Answer:

Complex roots for polynomials equations will always come in conjugate pairs.  Since 1-2i is a root, 1+2i will also be a root.  (Just switch the sign of the imaginary part to its opposite.)

Step-by-step explanation:

So far we have 1-2i and 1+2i as roots.  We need two more to make a 4th degree polynomial.

x=1 with multiplicity of 2 means that we count the root twice when we write down the polynomial: (x - 1)(x - 1) = (x - 1)2

Putting it all together, we can construct our polynomial of degree 4 as

y = f(x) = (x - 1)(x - 1)[x - (1-2i)][x - (1+2i)]

Multiply the factors (FOIL):

[x - (1-2i)][x - (1+2i)] =

x2 - (1+2i)x - (1-2i)x + (1-2i)(1+2i) =

x2 - x - 2ix - x + 2ix + (1 + 2i - 2i + 4) =

x2 - 2x + 5

(x - 1)(x - 1) = x2 - x - x + 1 = x2 - 2x + 1

Now multiply the two underlined expressions:

y = (x2 - 2x + 5)(x2 - 2x + 1)

= x4 - 2x3 + 5x2 - 2x3 + 4x2 - 10x + x2 - 2x + 5  by multiplying term by term

= x4 - 4x3 + 10x2 -12x + 5 by collecting like terms.

4 0
3 years ago
Samantha wants to put a fence around her backyard. She buys the fence in 6-foot sections and needs 12 sections. She spends a tot
Allisa [31]
Legnth of 1 section times number of sections=number of feet needed=6*12=72

72ft=850
divie both sides by 72
1ft=11.8055555

1 ft=$11.81
6 0
3 years ago
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