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3 years ago

Pls help me, i dont know what i’m doing

Mathematics

1 answer:

Keith_Richards [23]3 years ago

7 0

Answer:

The answer is in the pic above

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15x5x3 find the volume with lxwxh

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Answer:

225 units^3

Step-by-step explanation:

15x5x3 = 225

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The algebra mat below models the equation x+3=5

Akimi4 [234]

X + 3= 5

The answer to this equation is simply 2

to do this:

subtract 3 from both sides of the equation.

3 cancels out, and you are left with this

x=2

so, the answer is x=2

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3 years ago

Which expression represents the difference between 18 and an unknown number? A. 18 – n B. 18 + n C. 18 ÷ n D. 18 • n

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Your answer will be A. 18-n

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f left parenthesis x right parenthesis equals StartFraction 16 x squared Over x Superscript 4 Baseline plus 64 EndFractionf(x)=1

Jlenok [28]

Answer:

a) Yes

b) (2,0.8)

c) $(2\sqrt2,1), (-2\sqrt2,1)$

d) $x \in (-\infty,\infty)$

e) (0,0)

f) (0,0)

Step-by-step explanation:

We are given the following function in the question:

$f(x) = \displaystyle\frac{16x^2}{x^4 + 64}$

a) We have to check whether given point lies on the function or not.

$(-2\sqrt2,1)\\\\f(-2\sqrt2) = \displaystyle\frac{16(-2\sqrt2)^2}{(-2\sqrt2)^4 + 64} = \frac{128}{128} = 1$

b) Find value of f(x) at x = 2

$f(2) = \displaystyle\frac{16(2)^2}{(2)^4 + 64} =\frac{64}{80}= 0.8$

Thus, (2,0.8) lies on the graph of given function.

c) We have to find the value of x, when f(x) = 1

$1 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\x^4 -16x^2 + 64 = 0\\(x^2-8)^2 = 0\\x^2 - 8 = 0\\x = \pm 2\sqrt2$

$(2\sqrt2,1), (-2\sqrt2,1)$ lies on he graph of function.

d) Domain is the collection of all values of x for which the function is defined.

$x \in (-\infty,\infty)$

e) x-intercepts

This is the value of x such that the function is zero.

$0 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\16x^2 = 0\\x = 0$

f) y-intercept

It is the value of function when x is zero.

$f(0) = \displaystyle\frac{16(0)^2}{(0)^4 + 64} = 0$

The function passes trough origin.

5 0

3 years ago