(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28
anything to the 0 power is 1
(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28
using the power of power property to take the power inside
(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28
simplify
2^ -16 * 3^10 * 3^-8 /2*12 * 2^28
get rid of the division by making the exponent negative
2^-16 * 3^10 * 3^-8 *2*-12 * 2^28
combine exponents with like bases
2^(-16-12+28) * 3^(10-8)
2^(0) *3^2
anything to the 0 power is 1
1*9
9
Answer:
Final result :
x + 2
—————
x - 1
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 7 • 3 = 21
Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 .
-21 + -1 = -22
-7 + -3 = -10 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3
7x2 - 7x - 3x - 3
Step-4 : Add up the first 2 terms, pulling out like factors :
7x • (x-1)
Add up the last 2 terms, pulling out common factors :
3 • (x-1)
Step-5 : Add up the four terms of step 4 :
(7x-3) • (x-1)
Which is the desired factorization
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Rectangular parallelepiped, right rectangular prism)
lwh
Prism
bh
6x-12
Combine 2x and 4x = 6x
Combine -17 and 5 = -12
If it has rational coefients and is a polygon
if a+bi is a root then a-bi is also a root
the roots are -4 and 2+i
so then 2-i must also be a root
if the rots of a poly are r1 and r2 then the factors are
f(x)=(x-r1)(x-r2)
roots are -4 and 2+i and 2-i
f(x)=(x-(-4))(x-(2+i))(x-(2-i))
f(x)=(x+4)(x-2-i)(x-2+i)
expand
f(x)=x³-11x+20
