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seraphim [82]
2 years ago
10

The table shows the attendance at a high school musical from Wednesday through Saturday. Which expression would give the BEST es

timate of the total number that attended the musical? A) 300 + 400 + 600 + 600 B) 300 + 500 + 600 + 700 C) 400 + 500 + 600 + 600 D) 400 + 500 + 600 + 700
I NEED HELP ASAP!!!!!!
Mathematics
2 answers:
Leviafan [203]2 years ago
7 0
The answer is D) 400+500+600+700


You round 375<span><span> to 400
round 480 to 500
round 621 to 600
round 685 to 700

Hope this helps! </span></span>
Setler [38]2 years ago
4 0

Answer: D. 400 + 500 + 600 + 700

Step-by-step explanation:

The expression that best give the total estimate of the number in attendance of the high school musical would be gotten by rounding up or down to the nearest hundred.

If the figure in the tens position is greater than 50, we round up to the nearest hundred;

If the figure in the tens position is less than 50,we round down to the nearest hundred.

As such, 375 will be rounded up to 400

480 will be rounded up to 500

621 will be rounded down to 600 and lastly,

685 will be rounded up to 700.

The expression therefore is 400 + 500 + 600 + 700 making option D the right option.

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Answer:

Fraction=1/5=0.2

Step-by-step explanation:

If the student is 4m away from the school bell and moves 20m away, it means that he is 5 times more distant from the school bell and therefore should listen 5 times less, that is, 1/5 of the original sound.

Note: this as long as the initial environment conditions of 4m are the same at 20m

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What are equilateral triangles?
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Step-by-step explanation:

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Given a geometric sequence in the table below, create the explicit formula and list any restrictions to the domain.
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Answer:

B

Step-by-step explanation:

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here r = - 5 and a_{1} = - 4, hence

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Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
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