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3 years ago

14

Will's bedroom is 12,feet long and 8 feet wide. His closet is half the length and half the width of his bedroom. What is the are

a of Will's closet floor?

2 answers:

Sedaia [141]3 years ago

7 0

24 is the area of the closet floor

kicyunya [14]3 years ago

5 0

The answer is 24 because 6 x 4 = 24

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HELP URGENT!! Is the following relation a function?

zaharov [31]

Answer:

No.

Step-by-step explanation:

It does not pass the vertical line test, so the relation is not a function. This is because there are x-values that have several y-values. To be a function, a relation must have x-values that only have one y-value each.

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3 years ago

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Maru [420]

Answer:

y=x4

Step-by-step explanation:

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2 years ago

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Write the set of all real numbers greater than 19 and less than 32 in set-builder notation.

Aleks04 [339]

Answer: {xI x ∈ R, 19 < x < 32}

Step-by-step explanation:

This notation is:

{xI condition1, condition2, ...}

The first condition is:

From what set we take the values of x?

From the set of real numbers.

x ∈ R

The other conditions are the limitations that we have for x, in this case:

19 < x < 32

Then we can write this as:

{xI x ∈ R, 19 < x < 32}

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3 years ago

[need math help] Study buddies part #2

rosijanka [135]

Answer:

Part A) The distance between Whitney's house and Anh's house is 6.5 miles.

Part B) The total distance traveled by Whitney during the trip was 9.5 miles.

Step-by-step explanation:

Part A)

Notice that during Whitney's journey to Anh's house, her velocity was negative for some time. So, Whitney was travelling backwards. Hence, the total distance Whitney traveled will be greater than the actual distance from Whitney's house to Anh's.

So, instead, we can calculate Whitney's total displacement. Total displacement is given by:

$\displaystyle \text{Displacement}=\int_a^bv(t)\, dt$

Where <em>v(t)</em> is the velocity function.

So, the displacement of Whitney when she traveled from her house to Anh's house will be:

$\displaystyle \text{Displacement}=\int_0^{24}v(t)\, dt$

To calculate the integral, we can split it off at <em>t</em> = 11, <em>t</em> = 16, and <em>t</em> = 24.

The three regions represent three geometric figures, which we can use to calculate the area and then find the integral. Rewriting:

$\displaystyle \text{Displacement}=\int_0^{11}v(t)\, dt+\int_{11}^{16}v(t)\, dt+\int_{16}^{24}v(t)\, dt$

Now, we can calculate the area of each figure.

The first figure is a trapezoid with a height of 0.8 and two bases of 11 and 3. So, its area is:

$\displaystyle A_1=\frac{1}{2}(0.8)(11+3)=5.6\text{ miles}$

The second figure is a triangle with a height of 0.6 and a base of 5. So, its area is:

$\displaystyle A_2=\frac{1}{2}(0.6)(5)=1.5\text{ miles}$

Lastly, the third figure is another triangle will a height of 0.6 and a base of 8. So, its area is:

$\displaystyle A_3=\frac{1}{2}(0.6)(8)=2.4\text{ miles}$

However, notice that the second figure is below the <em>x</em>-axis. During that interval, Whitney was traveling backwards. Hence, we will subtract the second area from the rest of the areas.

Then the displacement will be:

$\displaystyle \text{Displacement}=5.6-1.5+2.4=6.5\text{ miles}$

So, the distance between Whitney's house and Anh's house is 6.5 miles.

Part B)

The total distance differs from displacement in that it includes all the distances in both directions. It is given by:

$\displaystyle \text{Distance}=\int_a^b|v(t)|\, dt$

In other words, all of our values are now positive. We will utilize the same strategy:

$\displaystyle \text{Distance}=\int_0^{11}|v(t)|\, dt+\int_{11}^{16}|v(t)|\, dt+\int_{16}^{24}|v(t)|\, dt$

Substitute. The only difference is that we will add 1.5 instead of subtracting it. So:

$\displaystyle \text{Distance} =5.6+1.5+2.4=9.5$

Therefore, in this instance, Whitney traveled a total of 9.5 miles to get to Anh's house.

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3 years ago

What are the answers to vocabulary check chapter review page 417?

UkoKoshka [18]

We need more information or a picture please :)

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3 years ago