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igomit [66]
3 years ago
6

The length of a new rectangular playing field is 4 yards longer than quadruple the width. If the perimeter of the rectangular pl

aying field is 488 yards, what are its dimensions?​
Mathematics
1 answer:
blsea [12.9K]3 years ago
5 0

Answer:

w = 48

w = 196

Step-by-step explanation:

Width = w

Length = l = 4 + 4w

Use the values for length and width above along with the given value for perimeter in the formula for perimeter.

P = 2l + 2w

488 = 2(4 + 4w) + 2w

488 = 8 + 8w + 2w

488 = 8 + 10w

488 - 8 = (8 + 10w) - 8

480 = 10w

(480)/10 = (10w)/10

48 = w

w = 48

The width is 48 yards.  Use this value to solve for length.

l = 4 + 4w

l = 4 + 4(48)

l = 4 + 192

l = 196

The length is 196 yards.

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