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VMariaS [17]
3 years ago
13

Find the like terms in the Algebraic Expression ( 2x +5x+10y+7)

Mathematics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

The answer is B. 2x , 5x.

Step-by-step explanation:

This is the answer because like terms are alike. For example: With 2x and 5x what do they have in common? They have the x in common. Another example is if you have (2 + 7 + 5x + 10y). What are the like terms? 2 and 7, because they are both integers. Also, if you are trying to solve an expression such as the last example, then you would add 2 + 7, because they are similar, so they can be added. So it would be (9 + 5x + 10y).

Hope this helps! :)

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Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
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2/sin theta. Hope it helps :}
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3 years ago
A grocery store manager received two shipments of oranges. According to the distributor of the oranges, the oranges in both ship
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The answer is
 <span>The two shipments have the same range of weights but a different mean weight.
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Listed below are the numbers of heroic firefighters who lost their lives in the United States each year while fighting forest fi
Marysya12 [62]

Answer:

Step-by-step explanation:

Hello!

Data

Year/Firefighters

2000: 20

2001: 18

2002: 23

2003: 30

2004: 20

2005: 12

2006: 24

2007: 9

2008: 25

2009: 15

2010: 8

2011: 11

2012: 15

2013: 34

<u>Common measures of variation</u>

<u>Variance</u>

S²= \frac{1}{n-1}[sumX^2-\frac{(sumX)^2}{n} ]

∑X= 20 + 18 + 23 + 30 + 20 + 12 + 24 + 9 + 25 + 15 + 8 + 11 + 15 + 34

∑X= 264

∑X²= 20² + 18² + 23² + 30² + 20² + 12² + 24² + 9² + 25² + 15² + 8² + 11² + 15² + 34²

∑X²= 5770

n= 14

S²= \frac{1}{13}[5770-\frac{(264)^2}{14} ]

S²= 60.90

<u>Standard deviation</u>

The standard deviation is the square root of the variance

S= √S²= √60.90= 7.80

<u>Coefficient of variation</u>

Is a relative standard deviation, it is defined as the division of the standard deviation (S) by the mean (X[bar)]. It has not units and is usually expressed in percentage. It shows the variability in relation to the mean.

C.V.= \frac{S}{X[bar]}*100 = \frac{7.80}{18.86}*100= 41.36%

The mean or average is a measurement of position and gives you an idea of the central value of the distribution of the data.

X[bar]= ∑X/n= 264/14= 18.86

<u>Range</u>

In the interval between the max and min values. It allows you to have an idea of the dispersion of the values.

R= Xmax - Xmin= 34 - 8= 26

Xmax= 34

Xmin= 8

<u>Inter Quartile Range</u>

Is the difference between Quantile 1 (C₁) and Quantile 3 (C₃). It shows the 50% mid values of the sample.

IQR= C₃ - C₁= 23.5 - 11.5 = 12

Quantile 1 (C₁) is the value that leaves 25% of the sample below and 75% of the sample above.

Pos1: n/4= 14/4= 3.5

The first quantile is the number between position 3 and position 4

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₁= (11+12)/2= 11.5

Quantile 3 (C₃) is the value that leaves 75% of the sample below and 25% of the sample above.

Pos3: n*3/4= 14*3/4= 10.5

The third Quantile is between position 10 and 11

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₃= (23+24)/2= 23.5

The measurements of variation don't allow you to know the origin of the data, that it is from consecutive years.

I hope it helps!

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10. The volume of the triangular prism is V=A_{base}\cdot H=\dfrac{1}{2} height \cdot base\cdot H, then

V=\dfrac{1}{2} \cdot 4\cdot 3.5\cdot 3.3=23.1.

11. The volume of the triangular pyramid is V=\dfrac{1}{3}A_{base}\cdot H=\dfrac{1}{3}\cdot \dfrac{1}{2} height \cdot base\cdot H, then

V=\dfrac{1}{3}\cdot \dfrac{1}{2} \cdot 4\cdot 3.5\cdot 3.3=7.7.

12. They have common base (common triangle). y=7.7, r=23.1, then r:y=23.1:7.7=3.

13. See 10 and 11 for notations in symbols.

6 0
3 years ago
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