The figure is the combination of trapezoid and square. Then the area of the figure will be 39 square meters.
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<h3>What is Geometry?</h3>
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
The figure is the combination of trapezoid and square.
Then the area of the geometry will be
Area = Area of trapezoid + Area of square
Area = 1/2 x (3 + 9) x 5 + 3 x 3
Area = 30 + 9
Area = 39 square meters
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Special Triangles Theorem
leg1=leg2=a
hypotenuse=a√2=10
Both Legs are 5√2 inches
This graph has a horizontal asymptote so it is an exponential graph. It also passes through two points (0,-2) and (1,3). The horizontal asymptote is at y=-3.
The unchanged exponential equation is y=a(b)^x +k
For exponential equations, k is always equal to the horizontal asymptote, so k=-3.
You can check this with the ordered pair (0,-2). After that plug in the other ordered pair, (1,3).
This gives you 3=a(b)^1 or 3=ab. If you know the base the answer is simple as you just solve for a.
If you don't know the base at this point you have to sort of guess. For example, let's say both a and b are whole numbers. In that case b would have to be 3, as it can't be 1 since then the answer never changes, and a is 1. Then choose an x-value and not exact corresponding y-value. In this case x=-1 and y= a bit less than -2.75. Plug in the values to your "final" equation of y=(3)^x -3.
So -2.75=(3^-1)-3.
3^-1 is 1/3, 1/3-3 is -8/3 or -2.6667 which is pretty close to -2.75. So we can say the final equation is y=3^x -3.
Hope this helps! It's a lot easier to solve problems like these given either more points which you can use system of equations with, or with a given base or slope.
One property of the diagonals of a rhombus is that they are perpendicular bisectors of each other. So 4 congruent right triangles will be formed when you draw the two diagonals. Considering one right triangle, we can solve for the two sides by dividing them by 2.
24 ft/ 2 = 12 ft
18 ft/ 2 = 9 ft
Using the Pythagorean Theorem, we can now solve for the hypotenuse which is the side of the rhombus.
side = √(12²+9²) = 15 ft
The answer is B.