Answer: 5 and 1/3 pounds of pasta
Step-by-step explanation:
Answer:
No order Pair fall on the graph
Step-by-step explanation:
The given Function is
...............(i)
Now to see whether these ordered pairs Lay on it we will put each ordered pair in the equation (i)
Lets take first ordered pair (1,1)
here x = 1
putting it in (i) gives

this is not equal to 1 so the order pair (1,1) does not fall on function 
Lets take second ordered pair (-1,-4)
here x = -1
putting it in (i) gives

this is not equal to -4 so the order pair (-1,4) does not fall on function 
Lets take third ordered pair (-2,-1/8)
here x = -2
putting it in (i) gives

this is not equal to -1/8 so the order pair (-2,1/8) does not fall on function 
Lets take fourth ordered pair (0,-1/2)
here x = 0
putting it in (i) gives

this is not equal to -1/2 so the order pair (0,-1/2) does not fall on function 
Answer:
a. x = -9 or x = -2
b. -5(x - 4)
c. x = -3 or x = 5
d. x = ±7
Step-by-step explanation:
a. First person;
y = x² + 11x + 18
y = x² + 9x + 2x + 18
y = x(x + 9) + 2(x + 9)
y = (x + 9)(x + 2)
y = x = -9 or x = -2
b. Second person;
y = -5x + 20
The common factor is 5.
y = -5(x - 4)
c. Third person;
y = x² - 2x - 15
y = x² - 5x + 3x - 15
y = x(x - 5) + 3(x - 5)
y = (x + 3)(x - 5)
y = x = -3 or x = 5
d. Fourth person;
y = x² - 49
Applying the difference of squares formula;
(a² - b²) = (a - b)(a + b)
y = x² - 49 = x² - 7² = (x - 7)(x + 7)
y = (x - 7)(x + 7)
y = x = ±7
Complete question:
A manufacturer has determined that a model of its washing machine has an expected life that is Exponential with a mean of four years to failure and irrelevant board burn-in period. He wants to testthe system and complete data collection. Find the probability that one of these washing machines will have a life that ends: (Note you can find the reliability of the washing machine life)
a) After an initial four years of washing machine service
b) Before four years of washing machine service are completed
c) Not before six years of washing machine service.
Answer:
a) 0.3679
b) 0.6321
c) 0.2231
Step-by-step explanation:
Given:
Mean, u= 4
/\ = 1/u
= 1/4 = 0.25
The cummulative distribution function, will be:
For x≥0,


a) After an intial four years:

P(x>4) = 0.3679
b) Before four years:

P(x<4) = 0.6321
c) Not before 6 years:

P(x>6) = 0.2231