The difference of two squares factoring pattern states that a difference of two squares can be factored as follows:
So, whenever you recognize the two terms of a subtraction to be two squares, you can factor it as the sum of the roots multiplied by the difference of the roots.
In this case, the squares are obvious: 
is the square of 
, and 
is the square of 
So, we can factor the expression as
![(x+2)^2 - (y+2)^2 = [(x+2)+(y+2)] - [(x+2)+(y+2)]](https://tex.z-dn.net/?f=%20%28x%2B2%29%5E2%20-%20%28y%2B2%29%5E2%20%3D%20%5B%28x%2B2%29%2B%28y%2B2%29%5D%20-%20%5B%28x%2B2%29%2B%28y%2B2%29%5D%20)
(the round parenthesis aren't necessary, I used them only to make clear the two terms)
We can simplify the expression summing like terms:
![(x+2)^2 - (y+2)^2 = [(x+2)+(y+2)][(x+2)-(y+2)] = (x+y+4)(x-y)](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%20-%20%28y%2B2%29%5E2%20%3D%20%5B%28x%2B2%29%2B%28y%2B2%29%5D%5B%28x%2B2%29-%28y%2B2%29%5D%20%3D%20%28x%2By%2B4%29%28x-y%29%20)
Answer: 2
Formula for cube is x^3 = 8
2^3 = 8
Answer:
There are 5 black counters in the bag.
Step-by-step explanation:
15 green counters in the bag
The proportion of green counters is given by:
So, we have that, the total is x. So
There are 30 total counters.
How many black counters are in the bag ?
A sixth of the counters are black. So
There are 5 black counters in the bag.
Answer:
if you rearrange to complete the square, you get (x^2-4)^2 +4
and seeing as anything squared will always be positive or zero, the lowest possible value for (x^2-4)^2 is 0, when x = 4
and 0 + 4 = 4, which is greater than 0, so positive
Step-by-step explanation:
Answer:
$88
Step-by-step explanation:
-38+126=$88
