Answer:
This scenario shows that there is more lemonade in the iced tea
Step-by-step explanation:
According to the given statement there is a mischievious child who is mixing the two beverages. The child says that only one cup of the iced tea was taken and put in the lemonade. Then, the child took only one cup of the lemonade-tea mixture that was just created and put it back into the pitcher of iced tea.
This scenario shows that there is more lemonade in the iced tea....
2 boxes=36 sticks
therfor
1 box=36/2=18 sticks
so if he has 5 boxes
18 times 5=90
he has 90 sticks
Answer:
y ≤ 5/2x + 7
Step-by-step explanation:
Rearrange the inequality so it looks like y = mx+b or in other terms, the y is on the left and everything else is on the right.
5x - 2y ≥ -14
-5x -5x
-2y ≥ -5x - 14
/-2 /-2 /-2
y ≤ 5/2x + 7
i changed the direction of the inequality sign because i divided everything by a negative 2.
<span>0.053
The standard deviation of a binomial variable is
sqrt(n*P*(1-P))
where n is the sample size and P is the probability of one of the outcomes.
The sample size is 55 and we'll assume that both male and female are equally likely outcomes.
standard deviation = sqrt(55*.5*.5) = 3.7081%
44% is 1.6181 standard deviations away from the mean of 50%.
Looking this up on a standard deviation chart gives .0526 probability which we'll round to 0.053</span>
Answer:
![c = - \frac{160}{9} + \frac{5}{9} f](https://tex.z-dn.net/?f=c%20%3D%20%20-%20%20%5Cfrac%7B160%7D%7B9%7D%20%20%2B%20%20%5Cfrac%7B5%7D%7B9%7D%20f)
Step-by-step explanation:
![f = \frac{9}{5} c + 32](https://tex.z-dn.net/?f=f%20%3D%20%20%5Cfrac%7B9%7D%7B5%7D%20c%20%2B%2032)
![5f = 9c + 160](https://tex.z-dn.net/?f=5f%20%3D%209c%20%2B%20160)
![- 9c = 160 - 5f](https://tex.z-dn.net/?f=%20-%209c%20%3D%20160%20-%205f)
![c = - \frac{160}{9} + \frac{5}{9} f](https://tex.z-dn.net/?f=c%20%3D%20%20-%20%20%5Cfrac%7B160%7D%7B9%7D%20%20%2B%20%20%5Cfrac%7B5%7D%7B9%7D%20f)
![c = - \frac{160}{9} + \frac{5}{9} f](https://tex.z-dn.net/?f=c%20%3D%20%20-%20%20%5Cfrac%7B160%7D%7B9%7D%20%20%2B%20%20%5Cfrac%7B5%7D%7B9%7D%20f)