x+y =27 sum of two numbers is 27
x=y+3 One of the numbers is three more than the other
substitute x=y+3 into the first equation
(y+3) + y = 27
combine like terms
2y + 3 = 27
subtract 3 from each side
2y = 24
divide by 2
y =12
x = y+3
x = 12+3
x =15
the two numbers are 12 and 15
Take the number with the variable on one side and the numbers alone on the otherside of the equal sign but don't forget to change the negative and positive sign
The first step to factorising this expression, is finding what is common in each term.
The GCF of 3, 2 and -4 is 1 therefore we will not have a coefficient of the outside terms.
Then we have st, su and sv
s is common in all of them therefore we can take out s.
So far we have s( )
Now for each term we must find what we multiply by s to reach it.
3st / s = 3t
2su / s = 2u
-4sv / s = -4v
Now just put these values inside the brackets.
s(3t + 2u - 4v)
Answer: Varies
Step-by-step explanation:
There would still be some Xs and Ys.
A = 6
tn = a + (n - 1)d
t4 = 6 + 3d = 12
3d = 12 - 6 = 6
d = 6/3 = 2
f(n + 1) = f(n) + 2