Answer:
m=21 and n=21
Step-by-step explanation:
In order to maximize the area of the rectangle, you want the two side lengths to be as equal to each other as possible.
In this case, we get that 2m+2n=84, so m+n=42. In our case, m and n can equal each other, so that gives us the maximum area of 441
Proof that this works:
If we had other dimensions, like m=20 and n=22, the area would be 440, slightly less than 442. If m=19 and n=23, the area becomes 437, which is even further off from 441.
Answer:
C and G
Step-by-step explanation:
Given
(x - 2)² = - 3x + 6 ← expand left side using FOIL
x² - 4x + 4 = - 3x + 6 ( subtract - 3x + 6 from both sides )
x² - x - 2 = 0 ← in standard form
(x - 2)(x + 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2 → G
x + 1 = 0 ⇒ x = - 1 → C
Answer:
24m tile for the floor and the 28+28+42+42=140m^2
Step-by-step explanation:
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Let's call them: W and L
Then area: A = W × L
We can replace: L = 2 × W
So: A = W × 2W=98→
2W^2=98 →W^2=98/2=49
→W=√49=7
→L=2×W=2×7=14
Conclusion: The rectangle is 7*14 ft
Hope this helps :)
5x + 75 = 120
5x = 45
x = 9