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Oxana [17]
3 years ago
11

Find the are of the polygon 16m 10m 20m 8m

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0

Answer:

Step-by-step explanation:

You might be interested in
Find the dimensions of a rectangle with perimeter 84 m whose area is as large as possible. (If both values are the same number,
dsp73

Answer:

m=21 and n=21

Step-by-step explanation:

In order to maximize the area of the rectangle, you want the two side lengths to be as equal to each other as possible.

In this case, we get that 2m+2n=84, so m+n=42. In our case, m and n can equal each other, so that gives us the maximum area of 441

Proof that this works:

If we had other dimensions, like m=20 and n=22, the area would be 440, slightly less than 442. If m=19 and n=23, the area becomes 437, which is even further off from 441.

3 0
4 years ago
Read 2 more answers
* please help*
strojnjashka [21]

Answer:

C and G

Step-by-step explanation:

Given

(x - 2)² = - 3x + 6 ← expand left side using FOIL

x² - 4x + 4 = - 3x + 6 ( subtract - 3x + 6 from both sides )

x² - x - 2 = 0 ← in standard form

(x - 2)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2 → G

x + 1 = 0 ⇒ x = - 1 → C

4 0
3 years ago
1:rosalie is refinishing her basement. 4m by 6m are the dimentions of rosalies rectangular basement.how much tile would she need
Artemon [7]

Answer:

24m tile for the floor and the 28+28+42+42=140m^2

Step-by-step explanation:

Trust me or else <u>YOU</u> be Major SUS

Also Mark me Brainiest please

3 0
3 years ago
the width of a rectangle is half as long as the length. The rectangle has an area of 98 square feet. What are the length and wid
Andrews [41]

Let's call them: W and L

Then area: A = W × L

We can replace: L = 2 × W

So: A = W × 2W=98→

2W^2=98 →W^2=98/2=49

→W=√49=7

→L=2×W=2×7=14

Conclusion: The rectangle is 7*14 ft

Hope this helps :)

6 0
3 years ago
If Jan adds 5 times her number to 75, she gets 120. What is Jan’s number?
goldenfox [79]
5x + 75 = 120
5x = 45
x = 9
3 0
4 years ago
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