Answer:
A quadratic function generally does not have an inverse except on a restricted domain. If the domain of the <em>original</em> function is restricted to x ≥ 0, then the inverse function is ...
Step-by-step explanation:
Start by interchanging x and "y", then solve for y.
y = 5x² +4 . . . . . . given
x = 5y² +4 . . . . . . with x and y interchanged
x -4 = 5y² . . . . . . subtract 4
(x -4)/5 = y² . . . . . divide by 5
√((x -4)/5) = y . . . take the square root . . . . x ≥ 4, y ≥ 0
Then, ...
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The graph shows the original f(x) and the "inverse", called f1(x). Note that it is only a reflection across y=x of the right half of the original function. That is, the inverse only exists for the original function when its domain is restricted to x ≥ 0. (The domain of the inverse function is x ≥ 4.)
You would take d times t seconds and find the answer
A+2=e
b-2=e
2c=e
d/2=e
dunno wat last part is but since they all equal e
a+2=b-2=2c=d/2
I am guessing that a+b+c+d=45 such that a+2=b-2=2c=d/2
interesting
make in terms of one thing
let's do a
a+2=b-2
a+4=b
a+2=2c
(a+2)/2=c
a+2=d/2
2(a+2)=d
sub
a+(a+4)+[(a+2)/2]+(2(a+2))=45
distribute some
a+a+4+(a+2)/2+2a+4=45
add like terms
4a+8+(a+2)/2=45
minus 8
4a+(a+2)/2=37
mult both sides by 2
8a+a+2=74
add like terms
9a+2=74
minus 2
9a=72
divide 9
a=8
sub back
a+4=b, 8+4=b=12
(a+2)/2=c, (8+2)/2=10/2=c=5
2(a+2)=d, 2(8+2)=2(10)=d=20
a=8
b=12
c=5
d=20
Answer:
Because the number would be multiplied by an even number, which is 2. If the number (odd or even) is multiplied by two, then the result would be an <em>even number</em>.
Proof:
2(1) = 2
2(6) = 12
2(7) = 14
2(3) = 6
The number would then be added by an odd number, which is 1. If an even number is added with an odd number, then the result would be an odd number.
Proof:
2 + 1 = 3
12 + 1 = 13
14 + 1 = 15
6 + 1 = 7
Answer:
x > 2
Step-by-step explanation:
2(x+5) = 2x + 10 -> 2x + 10 < 4+5x
Subtract 4 from each side.
2x +6 < 5x
Subtract 2x from each side
6 < 3x
2<x
So, x must be > 2