Answer:
The number of students who liked the book was 64.
Step-by-step explanation:
After reading a book for English class, 100 students were asked whether or not they enjoyed it.
Now, given that nine twenty-fifths of the class did not like the book.
So,
of the whole class did not like the book.
Then, the fraction of the class who did like the book was
.
Therefore, the number of students who liked the book was
. (Answer)
A = 6.7 :) hope this helps I double checked
Answer: (-2,-4) & (4,8) is the right answer
<span>8 1/2 + 6 4/5 = 15.3 or 15 3/10</span>
Answer:
The value is ![P(X < 0.50 ) = 0.43133](https://tex.z-dn.net/?f=P%28X%20%3C%20%200.50%20%29%20%3D%20%20%200.43133)
Step-by-step explanation
From the question we are told that
The population proportion is p = 0.51
The sample size is n = 75
Generally given that the sample size is large enough (i.e n > 30) the mean of this sampling distribution is mathematically represented as
Generally the standard deviation of this sample distribution is mathematically represented as
![\sigma = \sqrt{\frac{p(1- p)}{ n} }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%20%5Csqrt%7B%5Cfrac%7Bp%281-%20p%29%7D%7B%20n%7D%20%7D)
=> ![\sigma = \sqrt{\frac{0.51 (1- 0.51 )}{75} }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%20%5Csqrt%7B%5Cfrac%7B0.51%20%281-%200.51%20%29%7D%7B75%7D%20%7D)
=> ![\sigma = 0.058](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%200.058)
Generally the probability that in a random sample of 75 voters, fewer than 50% of the sample will vote for Candidate A is mathematically represented as
![P(X < 0.50 ) = P( \frac{ X - \mu_x }{\sigma } < \frac{ 0.50 - 0.51 }{0.0578 } )](https://tex.z-dn.net/?f=P%28X%20%3C%20%200.50%20%29%20%3D%20%20P%28%20%5Cfrac%7B%20X%20-%20%5Cmu_x%20%7D%7B%5Csigma%20%7D%20%3C%20%5Cfrac%7B%200.50%20%20-%20%200.51%20%7D%7B0.0578%20%7D%20%20%29)
![\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )](https://tex.z-dn.net/?f=%5Cfrac%7BX%20-%5Cmu%7D%7B%5Csigma%20%7D%20%20%3D%20%20Z%20%28The%20%20%5C%20standardized%20%5C%20%20value%5C%20%20of%20%20%5C%20X%20%29)
=> ![P(X < 0.50 ) = P( Z < -0.1730 )](https://tex.z-dn.net/?f=P%28X%20%3C%20%200.50%20%29%20%3D%20%20P%28%20Z%20%20%3C%20-0.1730%20%20%29)
From the z table the area under the normal curve to the left corresponding to -0.1720 is
![P( Z < -0.1730 ) = 0.43133](https://tex.z-dn.net/?f=P%28%20Z%20%20%3C%20-0.1730%20%20%29%20%3D%20%20%200.43133)
So
![P(X < 0.50 ) = 0.43133](https://tex.z-dn.net/?f=P%28X%20%3C%20%200.50%20%29%20%3D%20%20%200.43133)