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Alex_Xolod [135]
4 years ago
12

G6PD deficiency in humans is an X-linked recessive trait. If a homozygous dominant female (XGXG) has children with an affected m

ale (XgY), then what is the probability of the children being carriers?
Biology
1 answer:
Anvisha [2.4K]4 years ago
4 0

Answer:

Only the daughters will be carriers and the probability is 1 or 100%

Explanation:

Homozygous dominant female = X^{G} X^{G}

Affected male = X^{G}Y

X^{G} X^{G}   x   X^{G}Y

Offspring = X^{G}X^{g} (female), X^{G}X^{g} (females), X^{G}Y (male), X^{G}Y (male)

<em>For X-linked traits, male gender can either be affected or not affected, they cannot be carriers because the Y chromosome is hypothesized to not carry any gene. Since the two X chromosomes in female carry genes, they can be carriers for X-linked traits.</em>

Considering the female children only, the probability is 1 or 100%.

<em />

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