Answer:
n=4
Step-by-step explanation:
Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]
Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:
\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]
=> \[(8-n)*(4-n) =n*(n-4)*3\]
=> \[n-8 =3n\]
=> \[2n =8\]
=> n = 4
:(
the answer is 10!!!!!!
good luck
2 decimal places for regular . 3.14
Answer to the miscellaneous equation, is x=0
Miscellaneous equation are the equations which are not polynomial.
The question can be solved by:
Factorising:Splitting the terms to find the required solution
Completing the squares, etc
2ˣ -3ˣ=√(6ˣ-9ˣ)
-> (2ˣ -3ˣ)²=(3ˣ.2ˣ - 3²ˣ)
Squaring both sides,
-> 2²ˣ+3²ˣ- 2.3ˣ.2ˣ=(3ˣ.2ˣ - 3²ˣ)
-> 2²ˣ+2.3²ˣ-2.3ˣ.2ˣ-3ˣ.2ˣ=0
Factorising the terms,
-> 2ˣ(2ˣ-3ˣ) -2.3ˣ(2ˣ-3ˣ)=0
-> (2ˣ-3ˣ)(2ˣ-2.3ˣ)=0
Equating the braces to zero,
x=0 is the only solution.
Therefore, x =0 is the only solution
Learn more about miscellaneous equation: brainly.com/question/1214333
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