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2 years ago

Translate the sentence into an equation.

1 answer:

3 0

2 (x - 5) = 8

To solve, you use the distributive property as shown below!! :)

2x - 10 = 8
2x = 18
x = 9

Hope this helped you :)

You might be interested in

¿cual es el perimetro total de un paralelogramo obicuo cuya base mide 2∛54x² cm , y cuyo lado oblicuo mide 3∛54x²?

Step2247 [10]

Answer:

$p=10\sqrt[3]{54}x^2$

Step-by-step explanation:

We are given parallelogram

Since, two opposite sides of any parallelogram are always equal

Let's assume first side =a

second side =b

so, we get

$a=2\sqrt[3]{54}x^2$

$b=3\sqrt[3]{54}x^2$

now, we can find perimeter

perimeter=2a+2b

so, we get

$p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)$

we can simplify it

$p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2$

$p=10\sqrt[3]{54}x^2$ ................Answer

6 0

3 years ago

Read 2 more answers

What is the answer to <br> -4 + c = -11

wlad13 [49]

Answer: c = -7

Step-by-step explanation:

-4 + c = -11

c = -7

5 0

2 years ago

Gigi's home is located on the grid with the points (-6, 2), (-1, 2), (-7, 4) and (0, 4). She is planning to paint the entire roo

Marysya12 [62]

Answer:

EZZZZ

Step-by-step explanation:

7 0

2 years ago

the angle of elevation from a viewer to the top of a flagpole is 50°. the viewer is 40 ft away and the viewers eyes are 5.5 ft f

Margarita [4]

Answer:

53.2 feet

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC

$tan(50^o)=\frac{AC}{BC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(50^o)=\frac{h}{40}$

solve for h

$h=(40)tan(50^o)$

$h=47.7\ ft$

therefore

The height of the pole is

$h+5.5=47.7+5.5=53.2\ ft$

3 0

2 years ago

Find the zeros of the function and state their multiplicities. y=x^4-8x^2+16

Volgvan

$y=0\\\\ 
x^4-8x^2+16 = 0\\\\
(x^2)^2 - 2\cdot 4 \cdot x^2 + 4^2 = 0\\\\
(x^2 - 4)^2 = 0\\\\
(x^2 - 4)(x^2 - 4)=0\\\\
(x-2)(x+2) (x-2)(x+2) = 0\\\\
(x-2)(x-2) (x+2)(x+2) = 0\\\\
\Longrightarrow~~~ x_1 = 2;~x_2 = 2;~ x_3= -2;~x_4 = -2\\\\
\text{Conclusion:}\\\\
x_1 = x_2 = 2~~~ \text{double root}\\\\
x_3 = x_4 = -2~~~ \text{double root}\\\\
$

7 0

2 years ago