Question

Parabola,,Could you help me please??

Answer 1

Answer:

$\large \boxed{\sf \bf \sqrt{\dfrac{10}{3}}}$

Dimension of the rectangle is

$2\times\sqrt{\dfrac{10}{3}}\\ \\10-\dfrac{10}{3}=\dfrac{20}{3}$

Step-by-step explanation:

Hello,

$\text{The area is }2x(1-x^2) \\ \\\text{The derivative is }2(10-x^2)+2x(-2x)=2(10-3x^2)\\\\\text{The derivative is }0\text{ for} 10-3x^2=0 \\\text{so for } x=\sqrt{\dfrac{10}{3}}$

Thanks