Step-by-step explanation:
c >= 2
that means any value of c greater or equal to 2 is a valid solution. so, yes, 2 is a solution for this.
c < 2
that means any value of c smaller than 2 is a valid solution. so, no, 2 is not smaller than 2, so it is not a solution.
c < 3
that means any value of c smaller than 3 is a valid solution. so, yes, 2 is smaller than 3, so 2 is a solution.
3 < c
that means any value of c, for that 3 is smaller, is a valid solution. our in other words, any value for c larger than 3 is a valid solution. so, no, 2 is not larger than 3, so it is not a solution.
-8 < c
that means any value of c, for that -8 is smaller, is a valid solution. our in other words, any value for c larger than -8 is a valid solution. so, yes, 2 is larger than -8, so it is a solution.
I agree. There can't ever be 2 equal signs in A math problem
Q-2r=4, therefore: q=4+2r.
Plug the value of q into q+r=37, so you get:
4+2r+r=37
3r=37-4=33
3r=33
Therefore: r=11.
q-2r=4, but r=11, so:
q-2(11)=4
q-22=4
Therefore q=26.
Check if the answer is correct using second equation:
q=4+2r=4+2(11)=4+22=26.
So: q=26 and r=11.
6y - 4(y - 1) +6
6y - 4y -4(-1) + 6
6y - 4y +4 + 6
2y + 10
More specifically 32 goes into 82, 2.5625 times.
