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docker41 [41]
4 years ago
7

What is the value of 6[4-9.47]?

Mathematics
1 answer:
jasenka [17]4 years ago
8 0

Answer:

The solution is -32.82

Step-by-step explanation:

6[4-9.47]

6x(-5.47)

=-32.82

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Someone please help marking brainliest
Luda [366]
Answer: (1, 4)


Explanation: When using the method of elimination, the goal is to eliminate a variable by either adding or subtracting the 2 equations. For this question, you can choose either to eliminate X or Y. I’ll eliminate X as an example:

In order to eliminate a variable, the same variable in both equations must have the same coefficient.

(1) 3x+y=7
(2) 2x+5y=22

Multiply (1) by 2:

(3) 6x+2y=14

Multiply (2) by 3:

(4) 6x+15y=66

Now that X in both equations has the same coefficient of 6, you can subtract the two equations to officially eliminate the variable and solve for Y:

Subtract (4) from (3):

-13y=-52
y=4

Now that you have the value of Y, substitute that into either one of the equations to get X. I’ll use the first equation as an example:

3x+(4)=7
3x=3
x=1

Therefore, the point of intersection is (1, 4).


Hope this helps シ

3 0
3 years ago
Please help me now please
Kryger [21]

Answer:

0.4444444

Step-by-step explanation:

2/3 x 2/3 = 0.4444 repeating!

Hope this helps!

7 0
3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
If y= 1/3x and x= -18, find y
jarptica [38.1K]
   
\displaystyle \bf \\
x = -18 \\\\
y =  \frac{1}{3}\cdot x =  \frac{1}{3}\cdot -18 =  \frac{-18}{3} = \boxed{\bf -6}



3 0
3 years ago
Find the discriminant of the quadratic equation.<br><br> 2i2+6i=4
denpristay [2]

Answer: No solution

Would appreciate brainly <3

5 0
2 years ago
Read 2 more answers
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