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Sunny_sXe [5.5K]
3 years ago
6

What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

The zeros of the function are -0.488 and -7.39

Step-by-step explanation:

Given the quadratic function

f(x) = 2x²+16x-9

The zeros of the function is gotten at when f(x) = 0

2x²+16x-9 = 0

Using the general equation

x = -b±√b²-4ac/2a

From the equation, a = 2, b = 16 and c= -9

x = -16±√16²-4(2)(-9)/2(2)

x = -16±√256-72/4

x = -16±√184/4

x = -16+13.56/4

x = -16+13.56/4 and -16.13.56/4

x = --2.44/5 and -29.56/4

x = -0.488 and -7.39

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Answer:

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Step-by-step explanation:

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What are the coordinates of the point on the directed line segment from (-6, -6)(−6,−6) to (9, -1)(9,−1) that partitions the seg
GrogVix [38]

Answer:

(0, -4)

Step-by-step explanation:

The coordinates of the points from which the directed line segment extends = (-6, -6) to (9, -1)

The ratio the required point partitions the line = 2 to 3

The formula for finding the coordinate of a point that partitions a line AB into a ratio 'a' to 'b', where the coordinates of, A = (x₁, y₁) and B = (x₂, y₂) is given as follows;

\left(\dfrac{a}{a + b} \times (x_1 - x_2)+ x_1, \ \dfrac{a}{a + b} \times (y_1 - y_2)+ y_1 \right)

Therefore, the required point is located as follows;

\left(\dfrac{2}{2 + 3} \times (9 - (-6))+ (-6), \ \dfrac{2}{2 + 3}\times (-1 - (-6))+ (-6) \right) = (0, -4)

The coordinates of the point is (0, -4)

6 0
3 years ago
3 inches to the nearest 1/2 inch
DaniilM [7]

Answer:

6

Step-by-step explanation:

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Which of these expressions shows like terms?
Katen [24]

Answer:

the answer is 2× + 3×

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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15m+30n-44m+30n

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3 years ago
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