Answer:
The zeros of the function are -0.488 and -7.39
Step-by-step explanation:
Given the quadratic function
f(x) = 2x²+16x-9
The zeros of the function is gotten at when f(x) = 0
2x²+16x-9 = 0
Using the general equation
x = -b±√b²-4ac/2a
From the equation, a = 2, b = 16 and c= -9
x = -16±√16²-4(2)(-9)/2(2)
x = -16±√256-72/4
x = -16±√184/4
x = -16+13.56/4
x = -16+13.56/4 and -16.13.56/4
x = --2.44/5 and -29.56/4
x = -0.488 and -7.39
