Question

Solve for w. | – w|≥2 Write a compound inequality like 1 < x < 3 or like x < 1 or x > 3. Use integers, proper fractions, or improper fractions in simplest form.

Answer 1

Answer:

$-2 \geq w \geq 2$

Step-by-step explanation:

Given

$|-w| \geq 2$

Required

Solve for w

$|-w| \geq 2$

In absolution functions;

$|-w| = |w|$

So, the given expression can be rewritten as

$|w| \geq 2$

Removing the absolute sign, will gibe

$w \geq 2$ or $w \leq -2$

When the second inequality os rewritten, it gives

$w \geq 2$ or $-2 \geq w$

Reorder both inequalities

$-2 \geq w$ or $w \geq 2$

Lastly, both inequalities are combined

$-2 \geq w \geq 2$