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JulsSmile [24]
3 years ago
15

PLEASE HELP QUICK What is the slope-intercept form of the linear equation 2x + 3y = 6?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0

Answer:

y = - \frac{2}{3} x + 2

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + 3y = 6 into this form

subtract 2x from both sides

3y = - 2x + 6 ( divide all terms by 3 )

y = - \frac{2}{3} x + 2 ← in slope-intercept form


Inga [223]3 years ago
7 0

2x + 3y = 6

 3y = -2x + 6

   y = -2/3x + 2


answer

y = -2/3x + 2Answer:


Step-by-step explanation:

2x + 3y = 6

 3y = -2x + 6

   y = -2/3x + 2

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Step-by-step explanation:

This is absolute value, so anything inside of the bars is positive. Since the first -13 has bars around it it would be positive. But since the second - is outside of the 13 with bars, the 13 stays negative, so it would be 13-13. Hope this helps! :)

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2 years ago
Jorge makes fruit snacks for his friends. He uses 1 1/2 apples to make 3 fruit snacks.
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Jorge needs 1/2 apple to make the snack.

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Rewrite each of the following expressions without using absolute value bars.
Slav-nsk [51]

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A |x−4| if x>4

Step-by-step explanation:

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2 years ago
when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%​
Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%​

  • Selling price = cost price - discount ⇒ discount case
  • Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = \frac{160}{90}=\frac{16}{9}

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = \frac{20}{100} × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by \frac{16}{9} to find x

∵ 0.8x = \frac{16}{9}

- Divide both sides by 0.8

∴ x = \frac{20}{9}

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is \frac{20}{9}

- Find 20% of \frac{20}{9}

∵ Profit = 20% × \frac{20}{9} = \frac{20}{100}.\frac{20}{9}=\frac{4}{9}

- Add \frac{4}{9} to cost price to find the selling price

∴ The selling price of an orange = \frac{20}{9} + \frac{4}{9}

∴ The selling price of an orange = \frac{24}{9}

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ \frac{24}{9}

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

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Step-by-step explanation:

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