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jenyasd209 [6]
4 years ago
8

Which relation is also a function?

Mathematics
1 answer:
Dima020 [189]4 years ago
7 0

Answer:

Step-by-step explanation:

A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, given an element x in X, there is only one element in Y that x is related to. For example, consider the following sets X and Y.

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Based on the graph of the line below, which describes the relationship between the value of the y-intercept and the
stepan [7]

Answer:

y intercept = 3

m = \frac{1}{3} --- slope

Step-by-step explanation:

Given

The attached graph

Required

Determine the slope and the y intercept

The y\ intercept is at the point where x = 0.

From the graph:

y = 3;\ when\ x = 0

Hence,

y intercept = 3

Next, we calculate the slope using:

m = \frac{y_1 - y_2}{x_1 - x_2}

Where:

(x_1,y_1) = (0,3)

(x_2,y_2) = (9,6)

So, we have:

m = \frac{3 - 6}{0 - 9}

m = \frac{-3}{- 9}

m = \frac{3}{9}

m = \frac{1}{3}

6 0
3 years ago
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
Steven has a rectangular closet. The length is 10 feet and the width is 48 inches. Determine the area of the closet in square fe
Ne4ueva [31]

Answer:

  40 square feet

Step-by-step explanation:

You want the area in square feet of a closet that is 10 feet long and 48 inches wide.

<h3>Area</h3>

The area is the product of the length and width. For area to be in square feet, both dimensions must be in feet.

  12 in = 1 ft

  48 in = 4 ft

Then the area is ...

  A = LW = (10 ft)(4 ft) = 40 ft²

The area of the closet is 40 square feet.

7 0
2 years ago
Find the area of the shaded region. Use 3.14 for pi. Round to the nearest tenth.<br> r = 15<br> 110
Svetradugi [14.3K]

Answer:

110/360=11/36 (I will get back to this)

The area of the circle would be 225 pi using the formula pi r^2. So you multiply 225pi by 11/36 to find the area.  This rounds to 215.98

5 0
3 years ago
Read 2 more answers
Which is equivalent to <img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B9%7D%20%5E%7B%5Cfrac%7B1%7D%7B2%7Dx%20%7D" id="TexForm
Digiron [165]

For this case we have that by definition of properties of powers and roots, it is fulfilled that:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

So:

\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {\frac {1} {2}} {4} x} = 9 ^ {\frac {1} {8} x}

So, we have to:

\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {1} {8} x}

Answer:

9 ^ {\frac {1} {8} x}

Option B

5 0
3 years ago
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