Answer:
Step-by-step explanation:
Ok so the beaker is 200 water:800 acid
So she drains 100 from the acid and 100 from the water which equals
100:700
Then she adds 200 water:
300:700
there is 300 mL water in da beaker now
i might got it wrong tho
Answer:
There are 111 blue bags
Step-by-step explanation:
Let
x ----> the number of black bags
y ---> the number of blue bags
we know that
isolate the variable y
-----> equation A
----> equation B
substitute equation B in equation A
therefore
There are 111 blue bags
Division is repeated subtraction, in the loosest sense.
Answer:
46
Step-by-step explanation:
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
