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3 years ago

Determine whether the parabola y = −x2 + 15x + 8 opens up, down, left, or right.

1 answer:

7 0

Dy/dx=-2x+15

d2y/dx2=-2

Since the acceleration is a constant negative it has an absolute maximum value for y(x), thus it opens downward, as x decreases without bound as x approaches ±∞

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Graph the following figure in the coordin<br> X(0,1), Y(4, - 2), Z(-5,-2)<br> The perimeter is

andrezito [222]

Answer: I am in highschool and im doing this stuff. If you find out the answer let me know please.

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2 years ago

You are going running. For every mile you run, you burn 100 calories. In the graph and table below, m represents the number of m

Volgvan

I think you need to pit in a graph or draw one yourself, eat mile lable that you ran 100 miles and keep going

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3 years ago

Can anybody help with this

iris [78.8K]

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3 years ago

Find (f −1)'(a).<br><br> f(x) = 4 + x2 + tan(πx/2), −1 < x < 1, a = 4

Vinvika [58]

Answer:

The solution is $(f^{-1})'(a) = \frac{2}{\pi }$

Step-by-step explanation:

From the question we are told that

The function is $f(x) = 4 + x^2 + tan [\frac{ \pi x}{2} ]$ , -1 < x < 1 a = 4

Here we are told find $(f^{-1}) (a)$

Let equate

$f(x) = a$

$4 + x^2 + tan[\frac{\pi x }{2} ] = 4$

$x^2 + tan[\frac{\pi x }{2} ] = 0$

For the equation above to be valid x must be equal to 0

Now when x = 0

$f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]$

=> $f(0) = 4$

=> $0 = f^{-1} (4)$

Differentiating f(x)

$f(x)' = 0 + 2x + sec^2 (\frac{\pi x}{2} )\cdot \frac{\pi}{2}$

Now

since $0 = f^{-1} (4)$

We have

$f(0)' = 0 + \frac{\pi }{2} sec^2 (0)$

$f(0)' = \frac{\pi }{2}$

Now

$(f^{-1})'(a) = \frac{1}{(\frac{\pi}{2} )}$

$(f^{-1})'(a) = \frac{2}{\pi }$

3 0

2 years ago

3 fish weigh a total of 19 1/2 pounds one weighs 75/8 pounds another weighs 5 3/4 how much does the third fish weigh

marin [14]

First, you have to convert 75/8 into a mixed fraction which will be 9 3/8. 9 3/8+ 5 3/4 = 15 1/8. Finally, you do 19 1/2 - 15 1/8 which is 4 3/8

The answer is 4 3/8

3 0

2 years ago