Question

You are petitioning the city to hold a march for a 1 mile stretch of street. The street is 45 ft wide and each sidewalk is 5 ft deep on each side of the
street. Approximately how many people could fit in this 1 mile stretch if each person requires at least 2 square feet of space.
O 51,300 people
О 99,200 people
O 145,200 people
O 112,500 people
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Answer 1

Answer:

The approximate number of people that could fit in the 1 mile stretch is 145,200 people

Step-by-step explanation:

The length of the street = 1 mile stretch

The width of the street = 45 ft

The depth of each sidewalk = 5 ft

1 mile = 5,280 ft

Therefore;

The area of the side walk on each side of the street = 5 × 5,280 = 26,400 ft²

The area of both side walks = 26,400×2 = 52,800 ft²

The area of the street = 45 × 5,280 = 237,600 ft²

The total area of the street = The area of the street + The area of both side walks = 237,600 ft² + 52,800 ft²

The total area of the street = 290,400 ft²

The area occupied by one person is at least 2 ft²/person

Therefore, the approximate number of people that could fit in the 1 mile stretch = (The total area of the street)/(The area occupied by one person)

The approximate number of people that could fit in the 1 mile stretch = 290,400 ft²/(2 ft²/person) = 145,200 people

The approximate number of people that could fit in the 1 mile stretch = 145,200 people.