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ahrayia [7]
2 years ago
10

-7(4-x)+4≥-18+7x Solve the inequality

Mathematics
1 answer:
NikAS [45]2 years ago
7 0

Answer:

0 \geqslant 6

Step-by-step explanation:

- 7(4 - x) + 4 \geqslant  - 18 + 7x \\  - 28 + 7x + 4 \geqslant  - 18 + 7x \\  - 24 + 7x \geqslant  - 18 + 7x \\ 7x - 7x \geqslant 24 - 18 \\ 0 \geqslant 6

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1. if 50 people pay $50 a month for their cellphone bill how much money is it?
Murljashka [212]
1) 50*50, our 2500
2) 1500
3)1500
4) 900

just multiply t the number of people by the amount each pays
5 0
2 years ago
7/8 + ___ = 1 what is the missing numbers
Bezzdna [24]

the missing number is 1/8 i hope this helps chu

4 0
3 years ago
What is the reciprocal of 7/9
Amanda [17]
The reciprocal of a given fraction is obtained by flipping the elements of the fraction. This means that the current numerator becomes the denominator of the reciprocal and the current denominator becomes the new numerator. Thus, for the given fraction, the reciprocal is 9/7.
4 0
2 years ago
Line d has a slope of 3/2. Line e has a slope of -2/3. Are line d and line e parallel or
Ksivusya [100]

Answer:

We can determine from their equations whether two lines are parallel by comparing their slopes. If the slopes are the same and the y-intercepts are different, the lines are parallel. If the slopes are different, the lines are not parallel. Unlike parallel lines, perpendicular lines do intersect

6 0
2 years ago
Which of the following statement(s) describes the rate of change of f over the interval 1.5 ≤ x ≤ 3? Select all that apply.
Vesnalui [34]

2 Answers: Choice B and Choice C

The rate of change is 2.

The rate of change is constant.

======================================================

Explanation:

The first point on the left is when x = 1.5 and it has a height of y = 1

The point (1.5, 1) is on the line.

So is the point (3,4) for similar reasoning.

Compute the slope between those points

m = (y2-y1)/(x2-x1)

m = (4-1)/(3-1.5)

m = 3/(1.5)

m = 2

The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3  is a part of.

Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.

6 0
1 year ago
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