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4 years ago

11

a carpenter worked for four days to finish a repair job she charged $825 for 15 hours plus $270 for materials what is the Carpen

ters rate per hour

1 answer:

kvv77 [185]4 years ago

8 0

825 - 270
555 / 15
The carpenters rate is $37 a hour.

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If you had 1,100 blue berry's and 3 people took 61 each how many would you have left?

katrin [286]

Answer:

917.

Step-by-step explanation:

I'm 100% sure because 1,00-61-61-61=917.

Hope this helped lots and lots,

sincerely, me

6 0

4 years ago

Read 2 more answers

Is it ever possible that cos (A−B)=cos ⁡A−cos ⁡B? Why or why not?

Nookie1986 [14]

Answer:

The given equation is never possible i.e cos ( A - B ) ≠ cos A - cos B

Step-by-step explanation:

Given as :

Is cos ( A - B ) = cos A - cos B

To check this possibility , Let us put the value of angle A and B on both side of equation

Now, Let A = 60° and B = 30°

<u>From Left hand side equation </u>

cos ( A - B ) = cos ( 60° - 30° )

Or, cos ( A - B ) = cos 30°

∴ cos ( A - B ) = $\frac{\sqrt{3} }{2}$

or, cos ( A - B ) = 0.866

<u>From Right hand side equation</u>

cos A - cos B = cos 60° - cos 30°

Or, cos A - cos B = $\frac{1}{2}$ - $\frac{\sqrt{3} }{2}$

∴, cos A - cos B = 0.5 - 0.866

I.e cos A - cos B = - 0.366

So, Left hand side ≠ Right hand side

<u>Since while equating the values of angle A and b in the given equation on both sides, we get that the value of both sides are not equal , Thus we can say that the given equation is not equal to each other .</u>

Hence given equation is never possible i.e cos ( A - B ) ≠ cos A - cos B Answer

8 0

3 years ago

Which is the equation of a line that passes through the points (1,4) and (-1,1)

horsena [70]

Answer:

The equation of the line is y = 3/2x + 5/2

Step-by-step explanation:

To find the equation of this line, start by using the two points with the slope formula to find the slope.

m(slope) = (y2 - y1)/(x2 - x1)

m = (4 - 1)/(1 - -1)

m = 3/(1 + 1)

m = 3/2

Now that we have the slope, we can use that and either point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 4 = 3/2(x - 1)

y - 4 = 3/2x - 3/2

y = 3/2x + 5/2

3 0

3 years ago

The distance from the earth to the moon is 3.84 x 105 km

Anarel [89]

Part (a)

<h3>Answer: $3.84 \times 10^8 \text{ meters}$ </h3>

---------------------

Explanation:

Multiply by 1000 to go from km to meters.

This is because 1000 m = 1 km.

Multiplying by 1000 in scientific notation means we add 3 to the exponent 5. The 3 is because 1000 = 10^3.

So the $3.84 \times 10^5 \text{ km}$ becomes $3.84 \times 10^8 \text{ meters}$

===========================================================

Part (b)

Answer in standard form: 960,000 seconds

Answer in scientific notation: $9.6\times10^{5} \text{ seconds}$

---------------------

Work Shown:

$\text{distance} = \text{rate}*\text{time}\\\\\text{time} = \frac{\text{distance}}{\text{time}}\\\\\text{time} = \frac{3.84 \times 10^8 \text{ meters}}{400 \ \text{ m}/\text{s}}\\\\\text{time} = \frac{3.84 \times 10^8}{4 \times 10^2} \text{ seconds}\\\\\text{time} = \frac{3.84}{4}*\frac{10^{8}}{10^2} \text{ seconds}\\\\\text{time} = 0.96 \times 10^{8-2} \text{ seconds}\\\\\text{time} = 0.96\times 10^{6} \text{ seconds}\\\\$

$\text{time} = (9.6\times10^{-1})\times10^{6} \text{ seconds}\\\\\text{time} = 9.6\times(10^{-1}*10^{6}) \text{ seconds}\\\\\text{time} = 9.6\times10^{-1+6} \text{ seconds}\\\\\text{time} = 9.6\times10^{5} \text{ seconds}\\\\\text{time} = 960,000 \text{ seconds}\\\\$

To go from the scientific notation to standard form, move the decimal point 5 spaces to the right. The 5 is from the exponent.

3 0

2 years ago

A contractor is planning the acquisition of bulldozers needed for a new project in a remote area. From prior experience with thi

sleet_krkn [62]

Answer:

0.0256 ; 0.1536 ; 0.3456 ; 0.3456 ; 0.1296

Step-by-step explanation:

P, that each bulldozer will be operational for atleast 6 months = 0.6

p = 0.6 ; q = 1 - p = 1 - 0.6 = 0.4

Number of bulldozers purchased, n = 4

Probability that :

Exactly 0 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 0) = 4C0 * 0.6^0 * 0.4^4

P(x = 0) = 1 * 1 * 0.0256

P(x = 0) = 0.0256

Probability that :

Exactly 1 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 1) = 4C1 * 0.6^1 * 0.4^3

P(x = 1) = 4 * 0.6 * 0.064

P(x = 1) = 0.1536

Probability that :

Exactly 2 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 2) = 4C2 * 0.6^2 * 0.4^2

P(x = 2) = 6 * 0.36 * 0.16

P(x = 2) = 0.3456

Probability that :

Exactly 3 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 3) = 4C3 * 0.6^3 * 0.4^1

P(x = 3) = 4 * 0.216 * 0.4

P(x = 3) = 0.3456

Probability that :

Exactly 4 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 4) = 4C4 * 0.6^4 * 0.4^0

P(x = 1) = 1 * 0.1296 * 1

P(x = 1) = 0.1296

8 0

3 years ago