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2 years ago

Y+5.41=8.21 what is y

Mathematics

2 answers:

lana [24]2 years ago

6 0

Answer:

2.80

Step-by-step explanation:

emmasim [6.3K]2 years ago

3 0

Answer= 2.8

Step-by-step explanation:

y+5.41=8.21

y= 8.21-5.41

y= 2.8

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An isotope of iodine has a mass of 134 amu. How many neutrons does the

Nina [5.8K]

Answer:

The correct option is C: the isotope of iodine contains 81 neutrons.

Step-by-step explanation:

The mass (A) of the iodine isotope is given by:

$A = Z + N$

Where:

Z: is the number of protons

N: is the number of neutrons

For iodine Z= 53, so if A = 134 the number of neutrons is:

$N = A - Z = 134 - 53 = 81$

Therefore, the correct option is C. The isotope of iodine contains 81 neutrons.

I hope it helps you!

5 0

3 years ago

Assume that cost is 2 times more important than reputation and reputation is 3 times more important than compatibility with exis

dusya [7]

Let the weightage of Ease of Use be x
Ease of Use = x

Compatibility is 5 times more than ease of use:
Compatibility = 5x

Reputation is 3 times more important than compatibility:
Reputation = 3(5x)
Reputation = 15x

Cost is 2 times more important than reputation:
Cost = 2(15x)
Cost = 30x

So the weightage are:
Ease of Use : 1
Compatibility : 5
Reputation :15
Cost : 30

7 0

3 years ago

PLS HELP FOR BRAINLIST...

Ahat [919]

Answer is C ig I’m sowwy if I’m wrong

8 0

3 years ago

Solve for x. −5(x−4)=−30 Enter your answer in the box.

saveliy_v [14]

First divide both sides by - 5,

$x - 4 = 6$

Move the constant to the right side of the equation and change its sign (-4 => +4)

$x = 6 + 4$

Add the numbers,

$x = 10$

~~
I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

6 0

3 years ago

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago