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trapecia [35]
3 years ago
12

How would you simplify (log 27/logx) x (log x^2/log3)? I don’t think I did this correctly.

Mathematics
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

6

Step-by-step explanation:

logx 27  * log3 x^2

The first step is to convert to base 10

(log 27/logx) * (log x^2/log3)

27 = 3^3 so we can rewrite this

(log 3^3/logx) * (log x^2/log3)

log a^b  = b log a

(3 log 3/logx) * (2log x/log3)

We can cancel the log x in the numerator and denominator and the log 3 in the numerator and denominator

3 * 2

6

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(–2x + 4) + ( x – 11)
expeople1 [14]

Answer:

-x-7

Step-by-step explanation:

(-2x+4)+(x-11)

-2x+4+x-11

-x-7

7 0
3 years ago
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Scott has 10 1/2 yd of fabric to make banners for the community fair. He needs 1 3/4 yd for each banner.
Free_Kalibri [48]
(10 1/2) / (1 3/4) =
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7 0
4 years ago
A bag of corn tortilla chips costs 2.89 after a 15% discount. What is the original price?
Montano1993 [528]

Answer:

3.4

Step-by-step explanation:

Let the original price of the bag be = P, the selling price =2.89 after a 15% discount,

Then, Selling price= Original price- Discount on original price

2.89=P-P(0.15)

2.89=P(1-0.15)

2.89=0.85P

P=\frac{2.89}{0.85}

P=3.4

Thus, the original price was 3.4.

4 0
3 years ago
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the city park department is planning to enclose a play aea. one side of the area will be against an existing building, so no fen
SVEN [57.7K]

Answer:

length = 200 m

width = 400 m

Step-by-step explanation:

Let the length of the plaing area is L and the width of the playing area is W.

Length of fencing around three sides = 2 L + W = 800

W = 800 - 2L ..... (1)

Let A is the area of playing area

A = L x W

A = L (800 - 2L)

A = 800 L - 2L²

Differentiate with respect to L.

dA/dL = 800 - 4 L

It is equal to zero for maxima and minima

800 - 4 L = 0

L = 200 m

W = 800 - 2 x 200 = 400 m

So, the area is maximum if the length is 200 m and the width is 400 m.

8 0
3 years ago
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HELP PLEASE RIGHT NOW
lidiya [134]
A is the answer to this, think of it like a clock hope this helps!!
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3 years ago
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