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4 years ago

MULTIPLE CHOICE

1 answer:

3 0

Add the equations together so that you get 6x=-4, how I got their is cancel out the +/-3 and then add the -10+6=-4. Then you’d bring over the 6 and it would look like this x=-4/6 which you would simplify by dividing 2 into the 4 and 6 and should look like this x=-2/3

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Rachel is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove to get to the

lara31 [8.8K]

Answer:

$D(t)=-24t+166$

Step-by-step explanation:

Let

D(t) = the distance to the safe zone (measured in meters)

t = time (measured in seconds)

<u>Given:</u>

Rachel's rate = 24 meters per second

At $t_1=4$ seconds $D(t_1)=70$ meters

<u>Find:</u> D(t)

Rachel's rate is the slope of the function D(t). Since the distance is decreasing when the time is increasing, the slope must be negative.

Hence, the function expression is

$D(t)=-24t+b$

To find b, substitute $t_1=4$ and $D(t_1)=70:$

$70=-24\cdot 4+b\\ \\70=-96+b\\ \\b=70+96\\ \\b=166$

So,

$D(t)=-24t+166$

7 0

3 years ago

Two way to solve g+94=75

Tamiku [17]

Answer:

g = -19

Step-by-step explanation: You have to isolate g

g + 94 = 75

- 94 - 94

g = -19

Sorry if I'm incorrect...

5 0

3 years ago

Read 2 more answers

Which of the following statements is true in a one-way ANOVA? a. The critical value of the test will be a value obtained from th

Musya8 [376]

Answer:

d) All of the above

Step-by-step explanation:

A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).

In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.

In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.

This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.

The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.

Let's say we are comparing the means of k population. The degree of freedom would be = k - 1

The correct option here is (d).

All of the above

3 0

4 years ago

If you work:

faltersainse [42]

1920$

Step by step explanation:

6 0

3 years ago

Read 2 more answers