n > -6 is the inequality for 16 plus 5 times a number is more than the number minus 8
<em><u>Solution:</u></em>
Given statement is:
16 plus 5 times a number is more than the number minus 8
We have to write a inequality
From given statement,
16 plus 5 times a number is more than the number minus 8
Let the number be "n"
Therefore,
16 plus 5 times "n" is more than "n" minus 8
Here, "plus" means addition and "minus" means subtraction and "times" means multiplication
Thus the statement is translated into inequality as:

Simplify the inequality

Thus the soultion is n > -6
The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).
<h3>What are the intercepts of the equation as give in the task content?</h3>
The x-intercept of the given equation can be determined by setting values of y and z to zero.
The y-intercept can be determined by setting x and z to zero.
While the z-intercept can be determined by setting x and y to zero.
Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.
Therefore, we have; (15,0,0)
The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)
And hence, the z-intercept is; z = 30/6 = 5.
Read more on intercept;
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Answer:
X=10
Step-by-step explanation:
3x=30
3(10)=30
30=30
30+42=72
I hope this helps!
<h3>
Answer: 5 - 4i (choice A)</h3>
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Work Shown:
x = the other number
(5+4i)*x = 41
x = 41/(5+4i)
x = 41*(5-4i)/( (5+4i)*(5-4i) ) ..... see note below
x = 41*(5-4i)/( 41 )
x = (41/41)*(5-4i)
x = 5 - 4i
As a way to check, (5+4i)*(5-4i) = 5^2+4^2 = 25+16 = 41
The rule used is (a-bi)(a+bi) = a^2 + b^2
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Note: I multiplied top and bottom by (5-4i) to get rid of the imaginary term in the denominator.