1. y = 28
2. a = -5
3. solutions = one
Answer: -30b^2+76b+80
Explanation:
Multiply the second parenthesis by each term from the first parenthesis:
3b•2(-2•2+b+10)+4b•(-2b•2+b+10)+8(-2b•2+b+10)
Then distribute 3b•2 through the parenthesis
-24b^2+6b^2+60b+4b•(-2b•2+b+10)+8(-2b•2+b+10)
Then collect like terms
-30b^2+60b+40b-32b+8b+80
Collect like terms=
-30b+76b+80
Tossing two coins twice. I’m guessing the H and T stands for heads and tails.
<h2>Answer:</h2>
Option: D is the correct answer.
D. x < 397.9 and x > 402.1
<h2>Step-by-step explanation:</h2>
It is given that:
Each bag is advertised as weighing 400 grams.
Also, a bag must weigh within 2.1 grams in order to be accepted.
Hence, for the bag being accepted the weight must be no less than 2.1 gram from 400 gram and should be no more than 2.1 gram from 400 grams.
i.e. the weight of the bag must be such that:
400-2.1≤ x ≤ 400+2.1
i.e.
397.9 ≤ x ≤ 402.1
Hence, if the weight of the bag is less than 397.9 grams or is more than 402.1 grams then the bag will be rejected.
i.e. The range for the bag being rejected is: x<397.9 grams and x>402.1 grams.
I sort of know the metric system
