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4 years ago

Simplify -(-2a + 13) + (-9a - 2) - (-7a - 3)

Mathematics

2 answers:

nadya68 [22]4 years ago

5 0

-12 hope it helps :)

Diano4ka-milaya [45]4 years ago

4 0

Answer: the correct answer is -12

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A circle has a radius of 7cm . find the radian measure of the central angle ? that intercepts an arc of length 16cm .

Shalnov [3]

S=rtheta
theta=s/r
16/7=2.2857

6 0

3 years ago

A group of 2n people, consisting of n men and n women, are to be independently distributed among m rooms. Each woman chooses roo

vfiekz [6]

Step-by-step explanation:

Assume that

$X_i = \left \{ {{1, If , Ith, room, has,exactly, 1,man, and , 1,woman } \atop {0, othewise} \right.$

hence,

$x = x_1 + x_2+....+x_m$

now,

$E(x) = E(x_1+x_2+---+x_m)\\\\E(x)=E(x_1)+E(x_2)+---+E(x_m)$

attached below is the complete solution

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3 years ago

Identify the equation that dose not belong with the other three explain your reasoning pls

arsen [322]

If you take a moment and solve each equation (find the value
of the letter in each one), it'll jump out at you.

Here, let me do it for you. Why should you tire yourself.

5x = 20 . . . . . x = 4

4b = 7 . . . . . . b = 7/4

8w = 32 . . . . . w = 4

12y = 48 . . . . . y = 4

The second equation is not like the others.
It's the only one where the letter is not equal to 4 .

5 0

4 years ago

Read 2 more answers

Solve. 3^x = 81 a X= 2 b. X= 4 c. x=6 d. x =9 HELPPPPP

maw [93]

Answer:

B= x=4

3 x 3 x 3 x 3

3 x 3=9

9 x 9=81

3 0

3 years ago

Read 2 more answers

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago