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4 years ago

Simplify -(-2a + 13) + (-9a - 2) - (-7a - 3)

Mathematics

2 answers:

nadya68 [22]4 years ago

5 0

-12 hope it helps :)

Diano4ka-milaya [45]4 years ago

4 0

Answer: the correct answer is -12

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What does it mean to be “in the red?”

jeka57 [31]

Answer:

You have more debits than credits.

Step-by-step explanation

Being in the red means that you are in debt so im 90% sure its B

If you get this wrong then i am very sorry.This is my input :)

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3 years ago

I need the answers to 1 and 2 please help

Serggg [28]

Answer:

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3 years ago

Find the distance between w=1+2i and z=3-i

AlladinOne [14]

Answer:

The distance between w=1+2i and z=3-i is 3.61

Step-by-step explanation:

We need to find the distance between w=1+2i and z=3-i

The formula used is: $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=1, y_1=2, x_2=3, y_2=1$

We will use only real numbers and not i for calculating distance.

Putting values and finding distance

$Distance=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\Distance=\sqrt{(1-3)^2+(-1-2)^2} \\Distance=\sqrt{(-2)^2+(-3)^2} \\Distance=\sqrt{4+9} \\Distance=\sqrt{13}\\Distance=3.61$

So, The distance between w=1+2i and z=3-i is 3.61

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3 years ago

David made $80,950 last year. If his income is decreased by 7.25%, what is his adjusted

Taya2010 [7]

Answer:

75081

Step-by-step explanation: multiply 80950 by 0.9275

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3 years ago

A membership at Gisele’s Gym costs $145 to join and $3 for each visit. A membership at Freddie’s Fitness costs $75 to join and $

Mazyrski [523]

Step-by-step explanation:

You can do the equation 145+3v for Gisele’s Gym

For Freddie’s Fitness do the equation 75+5v and put in the number of visits for v

For example, for 33 visits Freddie’s fitness has a lower cost than Gisele’s gym. You could do 3x33 + 145 = ? for Gisele’s gym, and do 5x33 + 75 for Freddie’s Fitness, and then compare which one has a lower cost. But technically I just gave you one answer and shown you what you could do.

I’m not particularly sure if I’m correct but that’s how I would do it, sorry for the long wait, if you have any questions you can ask me :)

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3 years ago