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Stels [109]
3 years ago
11

Please help me and give answers​

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0
Easy just divide by 2 :)))
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Lena paid $18.96 for 3pounds of coffee. What is the cost per pound for this coffee
STatiana [176]

Answer:

6.32

Step-by-step explanation:

divide 18.96 by 3  and the outcome is 6.32

6 0
3 years ago
401 km 101 m – 34 km 153 m
Nikolay [14]

Given :

An expression D = 401 km 101 m – 34 km 153 m.

To Find :

Value of D.

Solution :

We know, 1 km = 1000 m.

So, 401 km 101 m =( 401000 + 101 ) m = 401101 m.

Also, 34 km 153 m = ( 34000 + 153 ) m = 34153 m.

Now, D is given by :

D = 401101 - 34153 m

D = 366948 m

Now, D = 366948 m = 366 km 948 m.

Therefore, the difference is 366 km 948 m.

Hence, this is the required solution.

4 0
4 years ago
Three friends shared 5/6 of a pizza equally. What fraction of the whole pizza did each friend get?
Ymorist [56]

Answer:

<em><u>5/18</u></em>

Step-by-step explanation

when you divide 5/6 by 3 you multiply 5/6 by 1/3 and you get 5/18!

I hope this helps!

4 0
4 years ago
I really need help plss​
Nataliya [291]
These are the steps good luck

5 0
2 years ago
Read 2 more answers
On a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24
Helen [10]

Answer:

30.06 degree Celsius at 4:00 PM.

Step-by-step explanation:

We have been given that on a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24 degrees C. At noon the air conditioner is turned​ off, and the people go home. The temperature outside is a constant 35 degrees C for the rest of the afternoon. The time constant for the building is 5 ​hr. We are asked to find the temperature inside the building at 4:00 PM.

We will use Newton's law of cooling to solve our given problem.

T(t)=M_0+(T_0-M_0)e^{-kt}, where

T(t) = Temperature after t hours.

M_0 = Temperature of surrounding environment,

k = Time constant.

\frac{1}{k}=5\Rightarrow k=\frac{1}{5}

Upon substituting our given values in Newton's cooling law, we will get:

T(t)=35+(24-35)e^{-\frac{t}{5}}

T(t)=35-11e^{-\frac{t}{5}}

To find the temperature at 4:00 pm, we will substitute t=4 in our formula as:

T(4)=35-11e^{-\frac{4}{5}}

T(4)=35-\frac{11}{e^{\frac{4}{5}}}

T(4)=35-\frac{11}{2.2255409284924674}

T(4)=35-4.9426186052894379601

T(4)=30.05738139471

T(4)\approx 30.06

Therefore, the temperature inside building would be approximately 30.06 degree Celsius at 4:00 PM.

5 0
3 years ago
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