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Bezzdna [24]
2 years ago
10

Solve (x - 3)^2 = 5 p please help

Mathematics
2 answers:
wel2 years ago
3 0

Hello!

Let's solve !

⇒ (x - 3)² = 5

⇒ x² - 6x + 9 = 5

⇒ x² - 6x + 4 = 0

⇒ x = -(-6) ± √36 - 4(1)(4) / 2

⇒ x = 6 ± √20 / 2 = 6 ± 2√5 / 2

⇒ x = 3 ± √5

∴ The solutions are x = 3 + √5 and x = 3 - √5.

Rzqust [24]2 years ago
3 0

Answer:

p=(x−3)25

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     (x-3)^2-(5*p)=0 

STEP1:

 1.1    Evaluate :  (x-3)2   =  x2-6x+9 

Equation at the end of step1:

x2 - 6x - 5p + 9 = 0

STEP2:

Solving a Single Variable Equation:

 2.1     Solve   x2-6x-5p+9  = 0

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Rationalise the denominator.
grin007 [14]

Let's see what to do buddy...

_________________________________

To do this, we have to multiply the face and denominator of the fraction by the denominator conjunction, which is :

(5 -\sqrt{2})

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

Reminder :

(a + b)(a - b) =  {a}^{2} -  {b}^{2}  \\

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

So we have :

\frac{1}{ 5-\sqrt{2} } \times  \frac{ 5+\sqrt{2}  }{ 5 +\sqrt{2}  } =  \frac{1 \times ( 5 +\sqrt{2}) }{(5- \sqrt{2} )( 5 +\sqrt{2})  } =  \\

The other is in the photo.

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

7 0
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