Question

The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had the largest percent error?

Answer 1

Student 4 has the largest percent error.

Step-by-step explanation:

The percent error of a measurement is given by

$p=\frac{|x-x_{true}|}{x_{true}}\cdot 100$

where

x is the value of the measurement

$x_{true}$ is the actual value

For student 1:

$x=49\\x_{true}=50$

Percent error:

$p=\frac{|49-50|}{50}\cdot 100=0.02\cdot 100=2\%$

For student 2:

$x=25.5\\x_{true}=25$

Percent error:

$p=\frac{|25.5-25|}{25.5}\cdot 100=0.0196\cdot 100 = 1.96\%$

For student 3:

$x=7.5\\x_{true}=8$

Percent error:

$p=\frac{|7.5-8|}{8}\cdot 100=0.0625\cdot 100 = 6.25\%$

For student 4:

$x=2.1\\x_{true}=1.6$

Percent error:

$p=\frac{|2.1-1.6|}{1.6}\cdot 100=0.3125\cdot 100 = 31.25\%$

So, student 4 has the largest percent error.

Learn more about errors:

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