Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
Z+5 that's it sorry had to put at least 20 characters so good luck. To clarify, it is z+5
Answer:
507,409
Step-by-step explanation:
if every 5 days the number quadruples (x4), and we want to know how many acorns fall after 30 days, we can divide 30 by 5 so we only have to calculate for the amount of time the take to quadruple.
30 ÷ 5 = 6
so we only have to quadruple the acorns 6 times.
if we start off with 124 acorns, this is what it will look like:
Day 0: 124 acorns
Day 5: 124 x 4 = 496 acorns
Day 10: 496 x 4 = 1984 acorns
Day 15: 1984 x 4 = 7936 acorns
etc... until day 30.
Day 30: 507904 acorns
I hope this was helpful :-)