Question

If h(x) = 5 + x and k (x) = StartFraction 1 Over x EndFraction, which expression is equivalent to (k circle h) (x)?

Answer 1

Answer:

The equivalent expression to  $(k\circ h)(x)$ is $\frac{1}{5+x}$

Therefore  $(k\circ h)(x)=\frac{1}{5+x}$

Step-by-step explanation:

Given that the functions h is defined by h(x)=5+x

and k is defined by $k(x)=\frac{1}{x}$

To find the composition of k and h that is  $(k\circ h)(x)$ :

$(k\circ h)(x)=k(h(x))$

$=k(5+x)$

$=\frac{1}{5+x}$

Therefore  $(k\circ h)(x)=\frac{1}{5+x}$

The equivalent expression to  $(k\circ h)(x)$ is $\frac{1}{5+x}$

Answer 2

Answer:

The answer is B

Step-by-step explanation: