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sdas [7]
3 years ago
8

Can someone help me with this question ??????????????

Biology
1 answer:
Vadim26 [7]3 years ago
6 0
The correct answer is B
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A receptor site that a molecule can bind to that changes the shape of the active site is called a(n)
shusha [124]

Answer:

a) allosteric site

Explanation:

An allosteric site is a site on an enzyme other than the active site where a molecule that is not a substrate binds. This changes the shape of the enzyme, making it harder for the substrate to bind and inhibits enzyme activity.

Hope that helps.

8 0
3 years ago
_____ is a by-product of respiration while ______is a by-product of photosynthesis.
vagabundo [1.1K]
Carbon dioxide is a byproduct of respiration while oxygen is a byproduct of photosynthesis.

Remember that a byproduct is a secondary product that is made in the synthesis of another. It is unintended and excreted.
6 0
3 years ago
Hereditary information for most traits is generally located in
Paha777 [63]

genes on chromosomes

3 0
2 years ago
Is dna replication describe as conservative or semi-conservative why
Lina20 [59]

Answer:

DNA replication is described as semi-conservative.

Explanation:

DNA replication is described as semi-conservative because each double helix formed comprises one strand from the helix from which it was copied and a new strand. That is, the replication of one helix results into two new copies of which each contains one of the original double stranded helix from which it was synthesized.

8 0
3 years ago
A certain buffer is made by mixing a weak acid HA and its conjugate base A–. When HA is present at a concentration of 0.5 mM and
MAVERICK [17]

Answer:The ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

Explanation:

The dissociation constant for formic acid = K_a=1.8\times 10^{-4}

Concentration of HA= 0.5 mM

Concentration of A^-= 0.1 mM

pH = 6.16

First we have to calculate the value of K_a.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[A^-}{[HA]}

Now put all the given values in this expression, we get:

6.16=pK_a+\log (\frac{[0.1]}{0.5})

pK_a=6.86

To calculate the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02.

Using Henderson Hesselbach equation :

7.02=6.86+\log \frac{[A^-]}{[HA]}

7.02=6.86+\log \frac{[A^-]}{[HA]}

\frac{[A^-]}{[HA]}=1.44

\frac{[HA]}{[A^-]}=0.69

Thus the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

7 0
3 years ago
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