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4 years ago

10

Solve each system by graphing y=2x-4

2 answers:

RoseWind [281]4 years ago

7 0

The thing to remember when you first graph an equation is,
y = mx +b
That equation is slope intercept form.
In slope intercept form, m is the slope of the equation.
y = 2x - 4 the slope is 2 (or 2/1) when graphing remember that it's always x/y
As you're graphing remember to go over 2 and up 1.
y = 2x - 4 the y intercept is -4. That's where you will start the graph on the y axis.
Hope that helps! :)

Blababa [14]4 years ago

3 0

Well if you have something for x you put it in the x and graph

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soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

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3 years ago

What is the mean of this data?<br><br> 12, 18, 11, 25, 38, 22

yanalaym [24]

Your answer is 21 for this one.

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3 years ago

Find all the real fourth roots of 0.0001.

Amiraneli [1.4K]

4th root is even so there can be negative solutions.
0.0001
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0.1 * 0.1 *0.1 * 0.1

4th root (0.0001) = 0.1 or -0.1

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3 years ago

A car is traveling at a constant speed of M miles per hour. Which coordinate is

lbvjy [14]

(1, M) this represents the miles per hour, which'll help find the other coordinates.

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3 years ago

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Factorise mx+cx+my+cy<br> With steps!!!<br> x=algebra x

avanturin [10]

Step-by-step explanation:

Hey there!

While factorising you remember to make it take common in most of the expression.

Here;

=mx+cx+my+cy

Take common 'x' in "mx+cx" and 'y' in my + cy.

= x(m+c) + y(m+c)

Now, "(m+c)" common again.

= (m+c) (x+y)

Therefore the factorized form of the expression in (m+c)(x+y).

<u>Hope it helps</u><u>.</u><u>.</u><u>.</u>

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3 years ago

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