Answer:
The first diagram is the correct one
Step-by-step explanation:
Notice that the subtraction of two complex numbers (z1- z2) implies the use of the opposite for the real and imaginary part of the complex number that is subtracted (in our case of z2). When we do such, the complex number z2 gets reflected about the origin (0,0), and then the real components of the two numbers get added among themselves and the imaginary components get added among themselves.
The diagram that shows such reflection about the origin [ z2 = 3 + 5 i being converted into -3 - 5 i] and then the combination of real parts [-3 + 5 = 2] and imaginary parts [-5 i - 3 i = - 8 i], is the very first diagram shown.
Answer: but I need the points sorri
You can build a small fortune or provide for a comfortable retirement with investment in standard savings accounts. . . . . . . . . . NOT !
Answer:
y = 12
Step-by-step explanation:
Divide both by 1/4
x = 1 when y = 32/3
When x = 1 1/8 = 9/8
y = 32/3 x 9/8
y = 12
Q1. The answers are (–1, 8), (0, 7), (3, 18)
<span>–3x + y ≥ 7
</span>Let's go through all choices:
<span>(–2, –3)
</span>(-3) * (-2) + (-3) ≥ 7
6 - 3 ≥ 7
3 ≥ 7 INCORRECT
(–1, 8)
(-3) * (-1) + 8 ≥ 7
3 + 8 ≥ 7
11 ≥ 7 CORRECT
(0, 7)
(-3) * 0 + 7 ≥ 7
0 + 7 ≥ 7
7 ≥ 7 CORRECT
(1, 9)
(-3) * 1 + 9 ≥ 7
-3 + 9 ≥ 7
6 ≥ 7 INCORRECT
(3, 18)
(-3) * 3 + 18 ≥ 7
-9 + 18 ≥ 7
9 ≥ 7 CORRECT
Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes
</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80
Jude needs at least 4 small boxes on the shelf: x ≥ 4
Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16
x ≥ 4 can include x ≤ 16
So, y can be 0: y ≥ 0
