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Bad White [126]
3 years ago
15

Clarence made a diagram to compare codominance and incomplete dominance.

Biology
2 answers:
emmasim [6.3K]3 years ago
8 0

The correct answer is both dominant alleles are fully expressed in offspring.      

In the incomplete dominance inheritance, one allele is not completely expressed over its paired allele and forms an intermediate trait, whereas in co-dominance, both the alleles express completely resulting into a new phenotype. For example AB blood group in humans.  

In the given question Y is the intersection of co-dominance set and incomplete dominance set. Thus, the area Y may have one dominant allele from co-dominance and one allele which is not completely dominant from incomplete dominance.

Therefore, the label to marked area Y may be - both dominant alleles are fully expressed in offspring.      


ss7ja [257]3 years ago
7 0

Answer:

The answer is both dominant alleles are fully expressed in offspring.      

Explanation:

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3 years ago
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Assume a population of purple and white flower pea plants (2000 total plants) is in Hardy-Weinberg equilibrium. The frequency of
lys-0071 [83]

Answer:

a) 0.48

b)

p= 0.4\\q=0.6

c) 720

Explanation:

Given ,

Frequency of white flower plant (p^2) is 0.16

Thus, frequency of dominant white allele (p) is equal to \sqrt{0.16} \\= 0.4

As we that, as per  Hardy-Weinberg equilibrium equation

p+q=1

Substituting the value of p in above equation, we get

0.4+q=1\\q=1-0.4\\q=0.6

a) As per Hardy-Weinberg equilibrium equation

p^2+q^2+2pq=1\\

Substituting the given and calculated values in above equation, we get -

0.4^2+0.6^2+2pq=1\\0.16+0.36+2pq=1\\2pq=1-0.16-0.36\\2pq=0.48

b) The frequency (decimal form) of the dominant allele

p= 0.4\\q=0.6

c) number of homozygous purple flower plants

= frequency of purple flower plants (q^2) * Number of flowers

= q^2 * 2000\\= (0.6^2)*2000\\= 0.36 * 2000\\= 720

8 0
3 years ago
Lamarck wrote an important book talking about
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3 years ago
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