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oksian1 [2.3K]
4 years ago
13

You have two flasks (labeled A and B) that each contain an equal population of normal animal cells. You place flask A in a machi

ne called a shaking incubator, which shakes the flask at 37°C and keeps the cells moving so as to not allow them to adhere to the bottom of the flask. Flask B is allowed to sit in an incubator (without shaking) at 37°C. If you let the cells in each flask grow for a week, which of the following results are you most likely to observe?
The cells in both flasks A and B will have grown significantly.
The cells in flask B will have grown significantly, but the cells in flask A will have not grown at all.
The cells in flask A will have grown significantly, but the cells in flask B will have not grown at all.
The cells in both flasks A and B will have not grown at all.
The cells in flask B will have grown significantly, but
Biology
1 answer:
Fudgin [204]4 years ago
5 0

Answe: The cells in flask B will have grown significantly, but the cells in flask A will have not grown at all.

Explanation:

Conditions for the growth of mammalian cells and non animal Cells are different.

For bacteria cells, shaking will be required which allows oxygen to freely enter the cells and provide more nutrients to promote growth. However, this is not the same for animal cells.

When culturing mammalian cells, a CO2 incubator running at 37° C is required as opposed to non-mammalian cells that can be grown in a non-CO2 or dry incubator.

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