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Use the multiplier 1.055
final = original x multiplier^n
where 'n' is the number of years
Sub the values in
final = 700 x 1.055^7
final = 1018.27
Subtract the values:
1018.27 - 700 = 318.27
Thus, he earns more than $275
He earns $43.27 more
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Answer: 0.2858
Step-by-step explanation:
Given : When fishing off the shores of Florida, a spotted seatrout must be between 24 and 30 inches long before it can be kept.
In a region of the Gulf of Mexico, the lengths of the spotted seatrout that are caught, are normally distributed with and .
Let x be the lengths of the spotted seatrout that are caught .
Using formula
For x= 24
For x= 30
Then, by using the z-value table , the probability that a fisherman catches a spotted seatrout within the legal limits will be :-
Hence, the probability that a fisherman catches a spotted seatrout within the legal limits = 0.2858
Percent formula : is/of = %/100
18 is what percent of 20...
is = 18
of = 20
% = x
sub and solve
18/20 = x/100
cross multiply
(20)(x) = (100)(18)
20x = 1800
x = 1800/20
x = 90 <=== so 18 is 90% of 20
Quadratic formula is derived from completing the square:
<span>ax² + bx + c = 0 </span>
<span>ax² + bx = −c </span>
<span>x² + b/a x = −c/a </span>
<span>Complete square on left side by adding (b/(2a))² to both sides: </span>
<span>x² + b/a x + (b/(2a))² = (b/(2a))² − c/a </span>
<span>(x + b/(2a))² = (b²−4ac)/(2a)² </span>
<span>x + b/(2a) = ± √(b²−4ac)/(2a) </span>
<span>x = −b/(2a) ± √(b²−4ac)/(2a) </span>
<span>x = (−b ± √(b²−4ac)) / (2a) </span>
<span>- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - </span>
<span>or </span>
<span>ax² + bx + c = 0 </span>
<span>ax² + bx = −c </span>
<span>4a (ax² + bx) = −4ac </span>
<span>4a²x² + 4abx = −4ac </span>
<span>Complete the square on left side by adding b² to both sides </span>
<span>4a²x² + 4abx + b² = b²−4ac </span>
<span>(2ax + b)² = b²−4ac </span>
<span>2ax + b = ± √(b²−4ac) </span>
<span>2ax = −b ± √(b²−4ac) </span>
<span>x = (−b ± √(b²−4ac)) / (2a)</span>