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stealth61 [152]
3 years ago
13

Can you help me with my Math, please?

Mathematics
2 answers:
creativ13 [48]3 years ago
6 0
The first poster is not an accurate representation of the painting, but the second poster is an accurate representation because the ratio between the first and original lengths did not equal the ratio between the first and original widths but the second poster's ratios were equal.
Brrunno [24]3 years ago
5 0

Answer:

Option C is the correct answer.

Step-by-step explanation:

The original painting dimensions are = 92 cm long by 73 cm high

The first poster measures 120 cm long by 100 cm high.

Lets check the ratio.

\frac{120}{92} by \frac{100}{73} This reduces to nowhere.

The second poster measures 138 cm long by 109.5 cm high.

Ratio is : \frac{138}{92} by \frac{109.5}{73}

This reduces to 1.5 by 1.5

Therefore we can say - The first poster is not an accurate representation of the painting, but the second poster is an accurate representation.

The ratio defines it all. The ratio of the first poster to original picture is not accurate but the ratio of second one is accurate.

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Negative 7 over 3, the whole multiplied by x minus 3 equals negative 52
Sliva [168]

Answer:

21

Step-by-step explanation:

6 0
3 years ago
If line tw is parallel to line SX , m ? 1 = 59 , and m ? 6 = 72?, what is m ? 8?
zubka84 [21]
I'm guessing 1 and 4, but I'm not sure. 
8 0
3 years ago
What is the value of t? 13t - 8.7 = 82.3
Dennis_Churaev [7]

Answer:

7

Step-by-step explanation:

13t = 82.3 + 8.7

13t = 91

t = 91/13 = 7

5 0
3 years ago
Read 2 more answers
a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel
adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

                             = 24000 - 750x + 2400x - 75x²

                             = 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

                                    = $ 150 + 165

                                    = $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0
3 years ago
Quiz: QZ 3.1-3.2
hram777 [196]

Answer:

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4 0
3 years ago
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